Theory of Structures Mock test – 3 || Civil Engineering Mock tests Welcome to your Theory of Structures Mock test - 3 Take an exciting test in Theory of structures You have only 15 mins to complete the test (15 Questions) Wish you all the best!!! Name Email 1. m1 and m2 are the members of two individual simple trusses of a compound truss. The compound truss will be rigid and determinate if A. m = m1 + m2 B. m = m1 + m2 + 1 C. m = m1 + m2 + 2 D. m = m1 + m2 + 32. For a strongest rectangular beam cut from a circular log, the ratio of the width and depth, is A. 0.303 B. 0.404 C. 0.505 D. 0.606 E. 0.7073. Maximum strain theory for the failure of a material at the elastic limit, is known as A. Guest's or Trecas' theory B. St. Venant's theory C. Rankine's theory D. Haig's theory4. The normal and tangential components of stress on an inclined plane through θ° to the direction of the force, will be equal if θ is A. 45° B. 30° C. 60° D. 90°5. In a shaft, the shear stress is not directly proportional to A. radius of the shaft B. angle of twist C. length of the shaft D. modulus of rigidity.6. Slenderness ratio of a long column, is A. area of cross-section divided by radius of gyration B. area of cross-section divided by least radius of gyration C. radius of gyration divided by area of cross-section D. length of column divided by least radius of gyration.7. The load on a spring per unit deflection, is called A. stiffness B. proof resilience C. proof stress D. proof load.8. The ratio of maximum and average shear stresses on a rectangular section, is A. 1 B. 1.25 C. 1.5 D. 2.09. The locus of the end point of the resultant of the normal and tangential components of the stress on an inclined plane, is A. circle B. parabola C. ellipse D. straight line.10. A compound truss may be formed by connecting two simple rigid frames, by A. two bars B. three bars C. three parallel bars D. three bars intersecting at a point.11. The ratio of crippling loads of a column having both the ends fixed to the column having both the ends hinged, is A. 1 B. 2 C. 3 D. 412. In case of principal axes of a section A. sum of moment of inertia is zero B. difference of moment inertia is zero C. product of moment of inertia is zero D. none of these.13. At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by A. depth of the section B. depth of the neutral axis C. maximum tensile stress at the section D. maximum compressive stress at the section14. The locus of the moment of inertia about inclined axes to the principal axis, is A. straight line B. parabola C. circle D. ellipse.15. A body is said to be in equilibrium if A. it moves horizontally B. it moves vertically C. it rotates about its C.G. D. none of these. Share to all